[Attempto] Should I expect RACE to figure this out?
Joshua TAYLOR
tayloj at cs.rpi.edu
Wed Mar 28 20:10:41 CEST 2012
I tried running the axioms through the consistency checker, and got
warnings "the room" (that if it was supposed to be anaphoric, then it
needed a referent). I tried adding the axiom "There is a room." and
the proof works:
Axioms: There is a room. A person is outside the room, or kicks a dog.
The person is inside the room. if a person is outside the room then
the person is not inside the room. if a person is inside the room then
the person is not outside the room.
Theorems: A person kicks a dog.
Parameters:
The following minimal subsets of the axioms entail the theorems:
Subset 1
2: A person is outside the room, or kicks a dog.
3: The person is inside the room.
4: If a person is outside the room then the person is not
inside the room.
Subset 2
2: A person is outside the room, or kicks a dog.
3: The person is inside the room.
5: If a person is inside the room then the person is not
outside the room.
//JT
On Wed, Mar 28, 2012 at 1:57 PM, Theodore H. Smith <delete at elfdata.com> wrote:
> I have this input for RACE.
>
> Axioms: A person is outside the room, or kicks a dog. The person is inside the room. if a person is outside the room then the person is not inside the room. if a person is inside the room then the person is not outside the room.
>
> Theorems: a person kicks a dog.
>
> Basically, in "Uncontrolled English", a person will kick the dog if he is inside the room. And he is inside the room. So he kicks the dog.
>
> RACE doesn't figure this out. Is the problem with this line?: "A person is outside the room, or kicks a dog."
>
> Is my input wrong? Or maybe RACE trips over that line?
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--
Joshua Taylor, http://www.cs.rpi.edu/~tayloj/
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